Take The Name Attribute Of An Option Element And Put It Into A Php Variable March 31, 2024 Post a Comment So I have an HTML dropdown that is created in php. echo ''; while($row = mysql_fetch_array($query)) { echo 'Solution 1: echo'<select id="myselect" name="myselect">'; echo'<option value="make_selection" id="make_selection" name="make_selection">Choose Your Category</option>'; while($row = mysql_fetch_array($query)) { echo'<option value="'.$row['categories'].'" id="'.$row['categories'].'">'.$row['categories'].'</option>'; } echo'</select>'; CopyAbove that:if($_POST){ $selection = $_POST['make_selection']; //do something with $selection //possibly redirect user using header('Location: page.php'); } CopySolution 2: Just for your own knowledge, this isn't how php works. Once this script is ran, it displays on the users browser, and you won't be able to do anything else without them submitting the form, or sending an ajax request.Solution 3: Your PHP runs on the server. The resulting HTML/JavaScript is viewed by the user in their browser on their client PC. You need to communicate between the two over HTTP (e.g. via Ajax/JavaScript or with a full round-trip to the server). Simply send a request when the dropdown's value changes.An answer that's any more specific would require an equivalently specific question.Solution 4: If you want the selected option to be passed to the next PHP page, you have to also assign a name attribute on the option.echo'<select id="myselect" name="myselect">'; while($row = mysql_fetch_array($query)) { echo'<option name="option[]" value="'.$row['categories'].'" id="'.$row['categories'].'">'.$row['categories'].'</option>'; $i++; } echo'</select>'; CopyThen on the receiving page:if(isset($_POST['option'])) { // process here print_r($_POST['option']); } CopyThe [] means PHP will see all of the options as values in an array, therefore they can be iterated over.Also, I would suggest using MySQLi, it stands for MySQL Improved. Share Post a Comment for "Take The Name Attribute Of An Option Element And Put It Into A Php Variable"
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